Question
In the gray atmosphere model, the Eddington approximation gives an equation for the fourth power of temperature as a function of this quantity. For 10 points each:
[10h] Name this quantity that equals opacity times distance. This quantity is the negative logarithm of transmittance.
ANSWER: optical depth [or optical thickness or absorbance; prompt on tau or OD or A] (Players should look to section 6.1 of Jermyn et al. 2023 for all of their Atmospheric Relations needs.)
[10m] This layer of a star is defined to have an optical depth of two-thirds. The temperature of this lowest layer of the solar atmosphere is used to calculate a star’s effective blackbody temperature.
ANSWER: photosphere [reject “photon sphere”]
[10e] The Sun’s chromosphere and corona are visible from Earth during these events. These events occur when the Moon passes between the Earth and the Sun.
ANSWER: solar eclipses [or total solar eclipses or stellar eclipses; prompt on eclipses or total eclipses]
<Forrest Weintraub, Science - Astronomy> ~23211~ <Editor: David Bass>
Data
Summary
| Tournament | Edition | Exact Match? | Heard | PPB | Easy % | Medium % | Hard % |
|---|---|---|---|---|---|---|---|
| 2024 PACE NSC | 06/08/2024 | Y | 36 | 14.72 | 97% | 19% | 31% |